Calculate Effective Spring Constant of Springs in Parallel

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Homework Help Overview

The discussion revolves around calculating the effective spring constant of springs in parallel, particularly when the springs have different spring constants and stretch distances due to their original lengths. The original poster expresses confusion about how to approach the problem when the stretch distances are not equal.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the implications of different stretch distances on the effective spring constant. The original poster attempts to use Hooke's Law to derive a formula but struggles with the differing stretches. Others question the necessity of factoring the equation and discuss the concept of effective spring constants in relation to orientation and constraints.

Discussion Status

The discussion is active, with participants offering various perspectives on the problem. Some suggest that the effective spring constant may not be well-defined under the given conditions, while others propose calculating forces at different distances. There is no clear consensus on how to proceed, but multiple interpretations and approaches are being explored.

Contextual Notes

The original poster mentions that the question arises from a school lab involving two springs of different lengths and constants, which adds complexity to the problem. There are uncertainties about averaging the stretches and how to define the effective spring constant in this context.

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Homework Statement


How do we calculate the effective spring constant of springs in parallel, where the springs have different spring constants and different stretch distances (because the original lengths of the springs are different).

Homework Equations



Hooke's Law --> Fx = kx

The Attempt at a Solution



If we assume the stretch distance of both springs are equal (x), and each spring constant is k1 and k2 respectively. Then the effective spring constant of the springs in parallel is:
F = k1x + k2x = (k1+k2)x
From above, one can see that the effective spring constant is k1+k2. However, I assumed the distance would be equal, therefore I was able to common factor it.

So, now my problem is, what happens if the stretch distances are different. Then the above equation becomes:
F=k1x1 + k2x2
As one can see, I cannot common factor anything.

EDIT: I'm ultimately looking to find the effective spring constant and in this case, I cannot common factor, so I cannot find the effective spring constant.
 
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Of course if the springs stretch by a different distance, you get F=k1x1 + k2x2. Why do you need to factor this? It's a perfectly good equation giving the force applied by the spring.
 
So how do I find the effective spring constant then?
 
There's no such thing as an effective spring constant because the force applied depends not only on position, but also on orientation (of whatever the springs are attached to).
 
Welcome to PF!

Hi Morass! Welcome to PF! :wink:
Morass said:
How do we calculate the effective spring constant of springs in parallel, where the springs have different spring constants and different stretch distances (because the original lengths of the springs are different).
ideasrule said:
There's no such thing as an effective spring constant because the force applied depends not only on position, but also on orientation (of whatever the springs are attached to).

I agree with ideasrule :smile:

If the springs are different lengths, then whatever's attached to them will have to start rotating, so how do you define a spring constant?

Is this a question from a book or test (if so, what's the full question), or have you just made it up out of interest?
 
Hi.

This question is from a lab that I am doing in school. For the lab, I had to use 2 different springs of different length and spring constant. Then I attached various masses and recorded the stretch when the 2 springs are put in parallel. Then teacher asked me to find the effective spring constant using this data. So what I did was I measured the stretch of each of the springs (and they are different because they were originally of different length) and then I took the average of those two stretches and sort of assumed that as the mutual stretch of the two springs so that I could use the original equation to find the spring constant of parallel springs: F = k1x+k2x = (k1+k2)x. - where x is the average of the two stretches of the springs.

I'm not sure if I can just average the two stretches but it seems reasonable :confused:
 
oh i see … the two springs remain the same length as each other because of some constraint on whatever is pushing or pulling …

eg two plates constrained to remain parallel, joined by two springs of different original lengths and spring constants.

Well, just calculate the two forces at each distance, y, and add them (I'm pretty sure it will depend on y and the "natural" lengths as well as on k1 and k2)
Morass said:
I'm not sure if I can just average the two stretches but it seems reasonable :confused:

erm :redface: … if you're not sure, then it isn't reasonable! :wink:
 
tiny-tim said:
Well, just calculate the two forces at each distance, y, and add them (I'm pretty sure it will depend on y and the "natural" lengths as well as on k1 and k2)

Hmm the thing is, I know you can add up the forces to find the total spring force on the object but how would I find the effective spring constant in that case? I think I'm averaging the two stretches in order to mimic the ideal case where the stretches are the same.

So i guess the final question is, how do I find the spring constant if I only know:
The total force of the two springs (Fg because the system is at equilibrium)
The stretch distance of each spring individually
 
Stop worrying about the future …

get the basic equation first, and then decide how to make it neat.
 

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