Calculate Electric Field at the Center of Semicircular Loop

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Homework Help Overview

The problem involves calculating the electric field at the center of a semicircular loop with a uniform positive charge distribution. Participants are exploring how to approach the integration of charge elements to determine the net electric field at a specific point.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss dividing the loop into charge elements and integrating over an angle. Some express uncertainty about how to express the charge element dq in terms of the angle dθ. Others suggest considering the symmetry of the problem and focusing on the vertical components of the electric field.

Discussion Status

The discussion is ongoing, with participants sharing hints and suggestions about the setup of the problem and the use of symmetry. There is a collaborative effort to clarify the expression for dq and to understand the components of the electric field.

Contextual Notes

Some participants indicate confusion regarding the initial steps and the mathematical expressions involved, particularly in relating dq to the angle dθ. The discussion reflects a mix of understanding and uncertainty about the problem setup.

kjintonic
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A semicircular loop of radius a carries positive charge Q distributed uniformly over its length.?
Find the electric field at the center of the loop (point P in the figure). Hint: Divide the loop into charge elements dq as shown in the figure, and write dq in terms of the angle d\theta. Then integrate over \theta to get the net field at P.


http://i533.photobucket.com/albums/ee336/shaneji_kotoba/RW-20-72.jpg

I don't know how to start this question...
 
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kjintonic said:
A semicircular loop of radius a carries positive charge Q distributed uniformly over its length.?
Find the electric field at the center of the loop (point P in the figure). Hint: Divide the loop into charge elements dq as shown in the figure, and write dq in terms of the angle d\theta. Then integrate over \theta to get the net field at P.


http://i533.photobucket.com/albums/ee336/shaneji_kotoba/RW-20-72.jpg

I don't know how to start this question...
You must have some idea how to start, have you tried using the hint?
 
Probably I can use E= (S)dE= (S)kdq/r^2 inwhich r=a
(S) is integral sign
 
kjintonic said:
Probably I can use E= (S)dE= (S)kdq/r^2 inwhich r=a
(S) is integral sign
You're on the right lines, how about writing dq in terms of d\theta?

HINT: Notice that the horizontal components will cancel so you need only consider the vertical components of the electric field.
 
hmmm... Sorry I kinda don't understant how to write dq in terms of dd\theta:(
 
bump?
 
First step you should note that by symmetry, one of field components in an axial direction is 0. Now you only have to find the other component. Set this problem up in the coordinate plane with point P at the origin. Draw a triangle for E in terms of E_x and E_y and theta. What can you say about how E_x is related to x? Write down the expression for dE, the differential electric field magnitude due to dq, then try to write dq in terms of \lambda dr, where lambda is Q/length.
 

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