Calculate energy lost to a rough surface

[Toliver96]

Homework Statement

A block of mass 2kg, moving at velocity 2.68 m/s, slides across a rough 3m surface with a coefficient of kinetic friction of .4. Calculate the energy lost to the 3m rough surface.
M=2kg
uK=.4
V=2.68 m/s
D=3m

Homework Equations

1/2mv^2
uK*Fn*D

The Attempt at a Solution

I used the kinetic energy equation of 1/2mv^2 to get 7.18J. Then I did uK*Fn*D to get 24J, where Fn is normal force and Gravity = 10m/s^2. I have no idea where to go from here.

 

[SammyS]

Homework Statement

A block of mass 2kg, moving at velocity 2.68 m/s, slides across a rough 3m surface with a coefficient of kinetic friction of .4. Calculate the energy lost to the 3m rough surface.
M=2kg
uK=.4
V=2.68 m/s
D=3m

Homework Equations

1/2mv^2
uK*Fn*D

The Attempt at a Solution

I used the kinetic energy equation of 1/2mv^2 to get 7.18J. Then I did uK*Fn*D to get 24J, where Fn is normal force and Gravity = 10m/s^2. I have no idea where to go from here.

What does that 24 J represent ?

 

[Toliver96]

It is supposed to be Jules, but I'm not sure if that's correct.

 

[SammyS]

It is supposed to be Jules, but I'm not sure if that's correct.

The units are Joules, but what does the 24 Joules represent?

 

[Toliver96]

The energy lost to the rough surface, but how can it lose more energy than what it has?

 

[SammyS]

The energy lost to the rough surface, but how can it lose more energy than what it has?

What happens to the block when the energy lost is equal to the initial Kinetic Energy ?

 

[Toliver96]

So the block will stop then, right?

 

[SammyS]

So the block will stop then, right?

Right.