Calculate Enthalpy Change: C6H5OH, CO2, H2O

[iRaid]

Homework Statement

determine the change in enthalpy for the following reaction from the enthalpies of formation for the reactants and products. (C6H5OH -165 kJ/mol, CO2 -393.15 kJ/mol, H2O -285.83 kJ/mol)

Homework Equations

The Attempt at a Solution

No idea, been a while since I did this...if ever

Any direction is appreciated.

 

[mpreds]

A change in enthalpy would indicate that there were parameters in the question that were changing. Do you have initial or final temperatures or any other data?

-Mark

 

[Borek]

Start with the balanced reaction equation.

 

[Telemachus]

$\Delta H= \sum_i \nu_i \Delta H^0_{products}- \sum_j \nu_j\Delta H^0_{reactants}$

As Borek says, you should start by having the balanced chemical equation.

 

[Chestermiller]

As Borek said, you have to start out with a balanced reaction equation. But you do realize that there is a reactant missing from the problem statement? Ask yourself, what is it the C6H5OH has to be reacting with to produce CO2 and H2O? (hint: it's a combustion reaction). So, what is the missing reactant. The next thing you have to recall is that, if this reactant is an elementary substance, what is its heat of formation? How is the heat of reaction related to the heats of formation of the products and the reactants?