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Calculate equilibrium constant?

  1. Aug 25, 2016 #1
    1. The problem statement, all variables and given/known data

    The following reaction was allowed to reach the state of equilibrium
    2A+B <====> C
    The initial amounts of reactant present in one litre of solution were 0.5 mole of A and 0.6 mole of B. At equilibrium the amounts were 0.2 mole of A and 0.45 mole of B and 0.15 mole of C. Calculate equilibrium constant


    2. Relevant equations

    Kc= [product]/[reactants]

    3. The attempt at a solution

    Kc= [0.15]/0.2^2×0.45
    Kc=0.15/0.018
    = 8.3
    In my book one of the option of mcq given is 8.3 but the option marked as correct is 11.7 which one is right? If 11.7 is correct then how?
     
  2. jcsd
  3. Aug 25, 2016 #2

    epenguin

    User Avatar
    Homework Helper
    Gold Member

    I do not see any reason your answer be wrong.

    The question contains the superfluous information of initial concentrations, but as you can check these are consistent with the final.
     
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