Calculate Flux & Current at Intersection of Neutron Beams

  • Thread starter Thread starter timman_24
  • Start date Start date
  • Tags Tags
    Current Flux
Click For Summary
SUMMARY

The discussion focuses on calculating the flux and current at the intersection of two monoenergetic neutron beams, I1=2*10^10 and I2=1*10^10, intersecting at a 30-degree angle. The flux is determined using the formula I1 + I2*cos(30), resulting in a value of 2.866*10^10 n/(cm^2-s). The current is represented as a vector J(Jx, Jy), where Jx is calculated as I1 + I2*cos(30) and Jy as I2*sin(30), yielding J(2.866*10^10 i + 0.5*10^10 j). The user expresses uncertainty regarding the distinction between flux and current, indicating a common area of confusion in the topic.

PREREQUISITES
  • Understanding of neutron beam intensity and its measurement
  • Familiarity with vector representation in physics
  • Knowledge of trigonometric functions and their application in physics
  • Basic concepts of flux and current in particle physics
NEXT STEPS
  • Study the principles of neutron beam interactions in physics
  • Learn about vector calculus in the context of physics
  • Explore the differences between flux and current in electromagnetic theory
  • Investigate practical applications of neutron beams in scientific research
USEFUL FOR

Students and professionals in physics, particularly those focusing on particle physics, neutron interactions, and vector analysis in scientific calculations.

timman_24
Messages
52
Reaction score
0

Homework Statement


Two monoenergetic neutron beams I1=2*10^10 and I2=1*10^10 intersect at an angle of 30 degrees. Calculate both the flux and current in the region where they intersect.


Homework Equations





The Attempt at a Solution



I lined the first I1 up parallel to the x-axis and tilted I2 30 degrees below I1 to make the calculations easier.

attachment.php?attachmentid=32029&stc=1&d=1297136282.png


Flux:

I believe flux is the amount of neutrons passing between the left side to the right side across this arbitrary surface area. I took the surface area to span the y-z axis with the flux passing along the x-axis.

To calculate the flux, I simple did:

I1 + I2*cos(30) = 2.866*10^10 n/(cm^2-s)

Current:

I believe the current to be the vector representation of the net flow. For this I did the following:

J(Jx,Jy) = Jx + Jy
Jx= I1 + I2*cos(30)
Jy= I2*sin(30)

J(Jx,Jy) = 2.866*10^10 i +.5*10^10 j

I am not 100% positive if this is the correct way to do this. I get confused sometimes between current and flux.

Any help would be much appreciated!
 

Attachments

  • cart.png
    cart.png
    612 bytes · Views: 1,011
Physics news on Phys.org
I guess a lot of people have trouble with flux and current? :-p
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
5
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
1
Views
4K