MCNP Flux and Power Calculation

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 4K views
mhovi
Messages
2
Reaction score
0
TL;DR
Axial and Radial Flux distribution of a reactor fuel assembly. Also Power distribution in each cell.
During a reactor assembly calculation, I need to determine axial and radial flux distribution over the surface. When I use F2 and F4 tally I get some value with unit 1/cm**2
What does the value means, neutron flux is supposed to be in the 10^14 range but output values are 10^2 range.
Can anyone guide me on how to determine axial and radial flux and also power distribution in a reactor assembly in MCNP6.2?
 
Physics news on Phys.org
I'll start with the basic stuff I know. Flux is particles per centimeter squared. In MCNP this is per source particle. Dimensionally particles per cm2 per particle cancel out to 1/cm2. ** just means to the power of.

Your actual flux number looks a little odd. I would check the tally divisors are correct, surface area if F2, volume if F4. Showing us your input file is helpful, without it this is just a guess.

Your question implies a critical reactor, and in a state of k=1 the neutron flux is whatever you want it to be. Set up the problem, get normalised results from MCNP and then calculate the answer using whatever values you know for the problem.

I had a bit of an idiot moment reading your question and for a short time was wondering why you would want flux resolved parallel to a cylinders surface. My googling found https://www.researchgate.net/publication/349683390_Calculation_of_the_Radial_and_Axial_Flux_and_Power_Distribution_for_a_CANDU_6_Reactor_with_both_the_MCNP6_and_Serpent_Codes_The_MCNP61_and_Serpent_1119_codes_were_used_for_Monte_Carlo_transport_calcul which ended my confusion and seems to address your problem. There is no example sadly, but it goes through the method quite well step by step. Have a read and see if it answers any other of your questions.