Calculate Heat of Combustion of C2H2

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SUMMARY

The molar heat of combustion of acetylene (C2H2) is calculated to be -1046.1 kJ/mol. This value is derived from the balanced chemical equation 2C2H2 + 5O2 => 4CO2 + 2H2O, using the heats of formation for liquid water (-285.8 kJ/mol), gaseous CO2 (-393.5 kJ/mol), and gaseous C2H2 (-26.7 kJ/mol). The calculation involves subtracting the total heat of reactants from the total heat of products, confirming that the reaction is exothermic.

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Homework Statement



Given the following enthalpies calculate the molar heat of combustion of C2H2.

Heat of formation of liquid water: -285.8 kJ/mol
Heat of formation of C2H2 (gas): -26.7 kJ/mol
Heat of formation of CO2 (gas): -393.5 kJ/mol

Homework Equations



Heat of combustion is heat of products minus heat of reactants.

The Attempt at a Solution



I balance the equation and I get:

2C2H2 + 5O2 => 4CO2 + 2H2O

The sum of the heat of the products minus the sum of the heat of the reactants, with the heat of oxygen being 0, is 2092.2 kJ.

Since there are two moles of C2H2 being combusted we must divide by 2 and we get 1046.1 kJ/mol.

Since this is combustion this is an exothermic reaction and so the heat of combustion is -1046.1 kJ/mole.

Is this correct?
 
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Logic is sound.
 
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