Calculate Height of Basketball Player's Jump

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SUMMARY

The discussion focuses on calculating the height of a basketball player's jump based on the time spent in the air, specifically 0.80 seconds. The key equation utilized is the equation of motion: s = ut + 0.5at², where 's' represents vertical distance, 'u' is the initial velocity, 'a' is acceleration, and 't' is time. The time in the air is divided equally between ascending and descending, leading to t1 = t2 = 0.4 seconds. By applying the acceleration due to gravity (approximately 9.81 m/s²), participants can derive the maximum height of the jump.

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Homework Statement



a basketball player jumped straight up to grab a rebound. if she was in the air for 0.80 second how high did she jump?

Homework Equations



i know the time but i don't know which equation to use

The Attempt at a Solution



i don't know how to solve yet
 
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0.8 = time to go up(t1) + time to come down(t2)

t1 = t2 = 0.8/2 (should be right)

vertical distance traversed use equation of motion

s = ut + 0.5at^2

can you go on from here?
 
Try s = 0.5 a t2, where a is the acceleration.
Given the time and acceleration (what is it?) you can find the largest distance (which is the top of her jump).
 

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