Calculate Impact Speed of Ball Bearings Dropped in Shot Tower

  • Thread starter Thread starter Kalie
  • Start date Start date
  • Tags Tags
    Impact Speed
Click For Summary
SUMMARY

The discussion focuses on calculating the impact speed of ball bearings dropped from a shot tower. The height required for the bearings to solidify in 4.5 seconds is determined to be 99.2 meters using the formula d = 0.5 * 9.8 * t². To find the impact speed, participants suggest using the kinematic equation v = initial velocity + (acceleration x time), where the acceleration is -9.8 m/s² and time is 4.5 seconds. This leads to a definitive calculation of the impact speed.

PREREQUISITES
  • Understanding of kinematic equations
  • Familiarity with gravitational acceleration (9.8 m/s²)
  • Basic knowledge of physics concepts related to free fall
  • Ability to perform calculations involving time and distance
NEXT STEPS
  • Research kinematic equations for motion under constant acceleration
  • Learn how to derive impact speed from height and time
  • Explore practical applications of shot towers in manufacturing
  • Investigate the effects of air resistance on falling objects
USEFUL FOR

Physics students, engineers, and anyone interested in the mechanics of falling objects and manufacturing processes involving shot towers.

Kalie
Messages
46
Reaction score
0
Ball bearings are made by letting spherical drops of molten metal fall inside a tall tower called a shot tower and solidify as they fall.
If a bearing needs 4.50 to solidify enough for impact, how high must the tower be?
What is the bearing's impact speed?

I got the answer for the first part correct it was 99.2
d=.5*9.8*4.5^2=99.2
but I am not sure how to approach the second part...

What is the bearing's impact speed?
I search all over but couldn't find an equation could someone help me with that.
All I need is the equation...thank you
 
Physics news on Phys.org
Look for the kinematics equations. Given all the information you have, you actually have a choice on the equation you want to use.

How about the intuitive: final velocity = initial velocity + (acceleration x time)
 
Kalie said:
Ball bearings are made by letting spherical drops of molten metal fall inside a tall tower called a shot tower and solidify as they fall.
If a bearing needs 4.50 to solidify enough for impact, how high must the tower be?
What is the bearing's impact speed?

I got the answer for the first part correct it was 99.2
d=.5*9.8*4.5^2=99.2
but I am not sure how to approach the second part...

What is the bearing's impact speed?
I search all over but couldn't find an equation could someone help me with that.
All I need is the equation...thank you

You know that v= -9.8 t m/s2 and t= 4.5 s!
 

Similar threads

Solving Ball Bearing Problem: Tower Height & Impact Velocity
  • · Replies 4 ·
Replies
4
Views
4K
How do I find the necessary height for a shot tower in this problem?
  • · Replies 13 ·
Replies
13
Views
15K
Calculating Impact Speed of a Ball Thrown Toward a Cliff
  • · Replies 1 ·
Replies
1
Views
2K
What is the Correct Calculation for h/H When Ball A Collides with Ball B?
  • · Replies 3 ·
Replies
3
Views
2K
Two balls, dropped with a delay of ##\Delta t##, meet after rebound
  • · Replies 34 ·
2
Replies
34
Views
2K
What Is the Average Force Exerted by a Ball on a Plate During Impact?
  • · Replies 5 ·
Replies
5
Views
3K
Dropping a ball and calculating its speed.
  • · Replies 10 ·
Replies
10
Views
6K
One ball dropped, another ball launched
  • · Replies 9 ·
Replies
9
Views
2K
Calculating Impact Speed of 4.00kg Cannon Ball Dropped from 55.0m
  • · Replies 3 ·
Replies
3
Views
6K
Calculating Impact Force of Dropping Metal Ball on Foam Mat
  • · Replies 3 ·
Replies
3
Views
4K