Calculate Limit - Wolfram Alpha

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SUMMARY

The discussion focuses on calculating limits using Wolfram Alpha and rewriting a series into a Riemann sum format. The specific transformation discussed involves expressing the series as \sum_{k=1}^{+\infty}{f(\frac{k}{n})\frac{1}{n}}, which is essential for applying the limit definition. The limit as n approaches infinity is confirmed to equal the integral \int_0^1{f(x)dx}, providing a clear method for evaluating the limit through integration.

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puzzek
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Calculate the limit of :

[PLAIN]http://www3.wolframalpha.com/Calculate/MSP/MSP3119g718e25g367ahi000057f7afh4fdhed60b?MSPStoreType=image/gif&s=9&w=150&h=57

Thanks for the help.
 
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Hi puzzek! :smile:

Can you rewrite this series to a Riemann sum. That is, rewrite it to the form

\sum_{k=1}^{+\infty}{f(\frac{k}{n})\frac{1}{n}}

for a function f. Wshy should you do this? Well, since you know that

\lim_{n\rightarrow +\infty}{\sum_{k=1}^{+\infty}{f(\frac{k}{n})\frac{1}{n}}}=\int_0^1{f(x)dx}
 
micromass Thank you!

your tip made it a lot easier !
 

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