Calculate mass from acceleration and radius

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SUMMARY

The discussion centers on calculating the mass of an imaginary planet using the gravitational acceleration and radius. The relevant equation is derived from Newton's law of universal gravitation, expressed as F = GM/r², where G is the gravitational constant (6.67 x 10^-11 N(m/kg)²). Given a radius (r) of 12 meters and an acceleration (a) of 2 m/s², the mass (M) is calculated as M = (4.63 x 10^-13 N)/(2 m/s²), resulting in a mass of 2.31 x 10^-13 kg. The conversation emphasizes the importance of understanding the relationship between gravitational force, mass, and acceleration.

PREREQUISITES
  • Understanding of Newton's law of universal gravitation
  • Familiarity with gravitational constant (G = 6.67 x 10^-11 N(m/kg)²)
  • Basic knowledge of acceleration and its relation to force (F = ma)
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the derivation of gravitational equations in astrophysics
  • Learn about the implications of gravitational acceleration on planetary formation
  • Explore density calculations for celestial bodies
  • Investigate the effects of varying radius and acceleration on mass calculations
USEFUL FOR

Students in physics, astrophysics enthusiasts, and anyone interested in gravitational calculations and planetary science.

kmh36
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Homework Statement


How do you calculate the mass of an object just from the acceleration from gravity and the radius?

Homework Equations


My thoughts were F=GM/r2, then once you find F, you can calculate mass by M=F/A
G= 6.67 x 10^11
r = 12
Acceleration = 2 m/s^2

The Attempt at a Solution


(6.67 x 10 ^-11) / 12^2 = 4.63 * 10 ^-13
M = (4.63 * 10 ^-13)/(2 m/s^2) = 2.31 ^-13 kg
 
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Hello 10 m/s, and welcome to PF :smile:

Acceleration from gravity due to another object happens to be independent of mass. You are missing an m in your ##F = {G Mm\over r^2}## that, with ## F= ma## goes over in ##a = {G M\over r^2}##.

[edit] compare gravitational acceleration at the surface of the earth:
G = 6.67E-11 N/(m/kg)2
M = 5.97E+24 kg
r = 6.37E+06 m
g = GM/r2 = 9.82E+00 m/s2
 
Last edited:
I'm sorry, I still don't understand! What is 10 m/s?
I didn't think my equations were right, but I really don't know what to try next. I don't know the mass which is really hanging me up.
 
10 m/s is 36 km/h, just a corny attempt at humor.

You don't know the mass in what kind of situation ? Could you be a bit more elaborate in the problem statement ?

Apparently you have two "things", 12 m apart, and "something" accelerates with 2 m/s2 ?
 
Ha, that is funny!

I'm trying to calculate the mass of an imaginary planet. All I have given to me is the radius (12m) and the acceleration due to gravity on that surface (which is 2 m/s2)
 
Well, then you're in business! So the problem statement is:

What is the mass of a planet with radius 12 m (!?), given that the acceleration due to gravity on the surface of that planet is 2 m/s2.

And you have the equation. Is it clear that GM/r2 is not a force but an acceleration ?

It's a very dense planet. Just for the fun of it, calculate the density in kg/m2 assuming its a sphere...

tip: work in symbols (a, G, M, r) as long as you can, until you have a final expression (a = ...) . Then check dimensions and then fill in numbers.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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