Calculate Mass of Ice Cube from Calorimetry Experiment

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SUMMARY

The discussion centers on calculating the mass of an ice cube using a calorimetry experiment involving a 95g aluminum calorimeter and 310g of water at room temperature. The initial temperature of the ice cube is -8.5°C, and the final equilibrium temperature is 17°C. The heat transfer equation used is m(al)C(al)(T(al) - T(final)) + m(w)C(w)(T(w) - T(final)) = m(ice)C(ice)(T(final) - T(ice)) + m(ice)L(fusion). The participant realizes the need to include the latent heat of fusion for the ice melting, affirming that only the mass of the ice cube should be multiplied by the latent heat on the right side of the equation.

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  • Understanding of calorimetry principles
  • Knowledge of specific heat capacities (C(al), C(water), C(ice))
  • Familiarity with the concept of latent heat of fusion
  • Ability to manipulate algebraic equations for heat transfer
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  • Review the concept of heat transfer in calorimetry experiments
  • Study the calculation of latent heat of fusion for ice
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Students in physics or chemistry, educators teaching thermodynamics, and anyone involved in calorimetry experiments or thermal energy calculations.

Myr73
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A cube of ice is taken from the freezer at -8.5C and placed in a 95g aluminium calorimeter filled with 310g of water st room temperature of 20C. The final situation is observed to be all water at 17C. What was the mass of the ice cube?

C (al)= 900, C (water)= 4186, C (ice)= 2100

m(al)= 0.095kg, m(water) = 0.310kg, m (ice)= ??
T (ice)= -8.5 C,T(final)= 17C, Twater= 20C, I assume the temperature of the aluminium container is the same of the water at 20C so T(al)= 20C,

heat lost= heat gained

I got --> m(al)C(al){ Tal- Tf} + m(w) C(w) { Tw- Tf) = m(ice) C(ice) { Tf- Ti}.
And then of course I would derive the formula to find the missing m(ice). However I am not getting the right answer. Can someone show tell me what I neeed to change in the formula?
 
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Did you take into account the latent heat of the solid ←→ liquid phase change?
 
Oh, I forgot that, umm.. so I would add m(w) Lfusion on the left side and m(ice) Lfusion on the right ??
 
Not both sides, just one. It melts, and stays melted.
 
oh right I was thinking I needed it for the water, but it doesn't change state, SO + m(ice) Lfusion on the right side? Is the rest of my equation right?
 

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