Calculate max height and t in max height?

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To calculate the maximum height and the time to reach that height for an object fired upwards at 3.000 m/s, the relevant formulas are derived from kinematic equations. The velocity at maximum height is 0 m/s, as the object momentarily stops before descending. Using the formula for maximum height, h = (v^2) / (2g), where v is the initial velocity and g is the acceleration due to gravity, the maximum height can be calculated. The time to reach maximum height can be found using t = v / g. Proper application of these formulas will yield the desired results.
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I need some help w/ this problem, u don't have to give me the whole thing maybe just the correct formulas for it. All your help is appreciated! Thanks!

If an object is fired up at a speed of 3.000 m/s at t= 0.0000s and reaches its max. height at time t. What is the velocity at the max. Height? g= -9.81 m/s/s. Calculate max height and t in max height?
 
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pleez just a little help!
 
You can use the formulas in this post.

Please don't post the same question several times.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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