Calculate Molar Specific Heat of Substance: 284J, 22.0°C to 39.5°C

[G-reg]

Homework Statement

A certain substance has a mass per mole of 55 g/mol. When 284 J is added as heat to a 32.0 g sample of this material, its temperature rises from 22.0°C to 39.5°C

And I know that the specific heat of this substance is 507.14 J/[kg(K)]

Homework Equations

Q = mc\DeltaT

The Attempt at a Solution

55 g/mol * (1/32g) = 1.71875mol

284J/[(1.71875mol)/(39.5-22)] = 9.44 J/[mol(K)]

however..this is wrong and now I'm not sure where to go..help pleeeease!

 

[rock.freak667]

Homework Statement

A certain substance has a mass per mole of 55 g/mol. When 284 J is added as heat to a 32.0 g sample of this material, its temperature rises from 22.0°C to 39.5°C

And I know that the specific heat of this substance is 507.14 J/[kg(K)]

I assume you used the information to find that.

c= 507.14 \frac{J}{kgK}


for the substance, 1 mol has how much mass in kg?