Calculate objects Position/acceleration as function of time

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SUMMARY

The discussion focuses on calculating an object's position and acceleration as functions of time based on the velocity equation vx(t) = a - bt², where a = 4.0 m/s and b = 2.0 m/s². The position function can be derived using the kinematic equation Xf = x1 + V1t + 1/2at², while acceleration is determined as the derivative of velocity. The maximum positive displacement from the origin is calculated using the equation V² = V1² + 2aD, yielding a displacement of 4 meters.

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Homework Statement


vx(t)=a-bt^2
a=4.0 m/s
b=2.0 m/s^2
At t=0 the object is at x=0

a)Calculate objects position as a function of time
b)Calculate objects acceleration as a function of time
c)What is objects maximium positive displacement from the origin


Homework Equations


vx(t)=a-bt^2


The Attempt at a Solution


a)Xf=x1 + V1t + 1/2at^2
Xf=0 + 4(0)+1/2(9.8)(0)^2

c)V2^2= V1^2 + 2aD
-V1^2/2a)=D
-16/-4=4

I'm particularly stumped on question a & b because I'm not quite sure what ithe question is asking and I'm not entirly confident that C is correct. Any help is appreciated.
 
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You could use the fact that velocity is just the derivative of displacement with respect to time, and then for (b) just recognize that acceleration is the derivative of velocity.
 

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