Calculate Pat's Weight at Earth's Double Radius

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SUMMARY

To calculate Pat's weight at an altitude twice the radius of the Earth, use the gravitational force formula Fg = G(m1)(m2)/r^2. Given Pat's mass of 65.5 kg, the gravitational acceleration at this altitude is reduced due to the increased radius, resulting in a weight of 71.4 N. The gravitational constant G is 6.67 x 10^-11, and the standard gravitational acceleration g at Earth's surface is 9.8 m/s². Understanding how gravitational force changes with distance is crucial for solving this problem.

PREREQUISITES
  • Understanding of gravitational force equations, specifically Fg = G(m1)(m2)/r^2
  • Knowledge of gravitational constant G = 6.67 x 10^-11
  • Familiarity with mass and weight concepts in physics
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Research the effects of altitude on gravitational force using the formula Fg = G(m1)(m2)/r^2
  • Learn about the relationship between mass, weight, and gravitational acceleration
  • Explore how gravitational acceleration changes with distance from the Earth's center
  • Study real-world applications of gravitational calculations in astrophysics
USEFUL FOR

Students studying physics, educators teaching gravitational concepts, and anyone interested in understanding the effects of altitude on weight and gravitational forces.

susan__t
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Homework Statement


Pat's mass is 65.5 kg on Earth's surface. What would Pat's weight be at an altitude twice the radius of the Earth


Homework Equations


Fg=G(m1)(m2)/r^2
G = 6.67X 10^-11
F=ma

We are not given the numerical radius of the Earth

The Attempt at a Solution


I tried to manipulate the formula a bit:
(using the gravitational law)
Fg = (65.5)x/ 2^2

And that got me nowhere.
I also know the answer is 71.4N but how you get there is what I don't understand.
 
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Fg=G(m1)(m2)/r^2

This equation should work. What are you using for each variable? Look up data you need. It's probably in your textbook somewhere.
 
While hage's solution is valid, I think we know g=9.8 for the surface of the Earth. Therefore, you can look at the equation and see how this force would change as R increases. Think about what is constant and what is changing.
 

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