Calculate Pat's Weight at Earth's Double Radius

  • Thread starter Thread starter susan__t
  • Start date Start date
  • Tags Tags
    Radius Weight
susan__t
Messages
20
Reaction score
0

Homework Statement


Pat's mass is 65.5 kg on Earth's surface. What would Pat's weight be at an altitude twice the radius of the Earth


Homework Equations


Fg=G(m1)(m2)/r^2
G = 6.67X 10^-11
F=ma

We are not given the numerical radius of the Earth

The Attempt at a Solution


I tried to manipulate the formula a bit:
(using the gravitational law)
Fg = (65.5)x/ 2^2

And that got me nowhere.
I also know the answer is 71.4N but how you get there is what I don't understand.
 
on Phys.org
Fg=G(m1)(m2)/r^2

This equation should work. What are you using for each variable? Look up data you need. It's probably in your textbook somewhere.
 
While hage's solution is valid, I think we know g=9.8 for the surface of the Earth. Therefore, you can look at the equation and see how this force would change as R increases. Think about what is constant and what is changing.
 

Similar threads

Replies
11
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
21
Views
3K
  • · Replies 4 ·
Replies
4
Views
16K
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K