Martian's Weight on Mars Calculated

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    Mars Weight
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Homework Help Overview

The discussion revolves around calculating the weight of a martian on Mars given his mass and some planetary data. The subject area includes gravitational physics and the application of Newton's law of universal gravitation.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of the gravitational force equation and the need to find the gravitational acceleration on Mars. There are questions about the correct application of constants and the method to derive weight from mass.

Discussion Status

The conversation is ongoing with participants providing hints and questioning the original poster's approach. Some have suggested using gravitational field strength data, while others emphasize the importance of understanding the underlying concepts rather than just obtaining an answer.

Contextual Notes

There is mention of a data sheet that may contain gravitational field strengths for various planets, which could aid in the calculations. The original poster's previous attempts and formatting are also noted as a point of discussion.

AmericanBoy
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Homework Statement


On Mars, a martian tells you he has 35.0kg of mass. What is his weight on mars?

Mars Info:
Mass= 6.42x10^23
Radius= 3.40x10^6
Radius of Orbit about sun= 2.30x10^11

Homework Equations


FG=GM1M2/R^2

The Attempt at a Solution


I tried using the equation above, but i got 4.28x10^13. I am pretty sure you have to find Gravity on Mars and multiply it with the martians mass because mass to weight on Earth is mass(kg) x 9.8 m/s^2 (Gravity on Earth)(Hopefully this is a better format than my last thread.
 
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Btw, please show how you got the answer.
 
it sounds like you forgot to multiply by G.. please post all working.
 
That's the problem. How do you find G on Mars?
 
AmericanBoy said:
That's the problem. How do you find G on Mars?
G is a universal constant (not to be confused with g).
 
If you have a data sheet, the gravitational field strengths for various planets may be given. This would allow you to use W=mg.
 
CheesyPeeps said:
If you have a data sheet, the gravitational field strengths for various planets may be given. This would allow you to use W=mg.
I'm sure AmericanBoy is supposed to use the information about Mars provided.
 
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CheesyPeeps said:
If you have a data sheet, the gravitational field strengths for various planets may be given. This would allow you to use W=mg.
How would information like this help the OP who is trying to learn the fundamentals?

Chet
 
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It looks like you have the correct formula, you just plug everything into get the final answer. (6.67 x 10^-11N·(m/kg)^2)(35kg)(6.42 x 10^23kg) / (3.4 x 10^6m)^2.
 

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