fabiancillo
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Thread moved from the technical forums to the schoolwork forums
The discussion focuses on calculating principal inertias for a painted area using the formulas for moment of inertia with respect to the x and y axes. The relevant equations provided are \(I_x = \frac{bh^3}{12}\) and \(I_{xy} = \frac{b^2h^2}{24}\). Participants emphasize the importance of the superposition property of moment of inertia and suggest breaking the shape into simpler components for calculation. The parallel axis theorem is also mentioned as a necessary concept for solving the problem.
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I am totally blockedergospherical said:Keeping in mind the superposition property of the moment of inertia, can you split this shape up into pieces and evaluate ##I_x## and ##I_y## for them separately?
That's also called a moment of inertia!fabiancillo said:I am totally blocked
Fixed the LaTeX by doubling the dollar signs.fabiancillo said:$$I_x = \displaystyle\frac{bh^3}{12}$$
$$I_{xy} = \displaystyle\frac{b^2h^2}{24}$$