Calculate Principal Inertias - Exercise Hint

  • Thread starter Thread starter fabiancillo
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on calculating principal inertias for a painted area using the formulas for moment of inertia with respect to the x and y axes. The relevant equations provided are \(I_x = \frac{bh^3}{12}\) and \(I_{xy} = \frac{b^2h^2}{24}\). Participants emphasize the importance of the superposition property of moment of inertia and suggest breaking the shape into simpler components for calculation. The parallel axis theorem is also mentioned as a necessary concept for solving the problem.

PREREQUISITES
  • Understanding of moment of inertia
  • Familiarity with the superposition property of moment of inertia
  • Knowledge of the parallel axis theorem
  • Basic proficiency in LaTeX for mathematical expressions
NEXT STEPS
  • Study the application of the parallel axis theorem in moment of inertia calculations
  • Learn how to derive moment of inertia formulas for different geometric shapes
  • Practice breaking complex shapes into simpler components for inertia calculations
  • Explore advanced topics in structural mechanics related to inertia
USEFUL FOR

Students and professionals in engineering, particularly those specializing in structural mechanics and materials science, will benefit from this discussion.

fabiancillo
Messages
27
Reaction score
1
Thread moved from the technical forums to the schoolwork forums
Hello I have problems with this exercise

For the painted area calculate inertias with respect to the x and y axes and the principal inertias

Hint:
$I_x = \displaystyle\frac{bh^3}{12}$
$I_{xy} = \displaystyle\frac{b^2h^2}{24}$

Thanks
 

Attachments

  • inerciaprincipals.png
    inerciaprincipals.png
    158.2 KB · Views: 139
Physics news on Phys.org
Keeping in mind the superposition property of the moment of inertia, can you split this shape up into pieces and evaluate ##I_x## and ##I_y## for them separately?
 
ergospherical said:
Keeping in mind the superposition property of the moment of inertia, can you split this shape up into pieces and evaluate ##I_x## and ##I_y## for them separately?
I am totally blocked
 
fabiancillo said:
I am totally blocked
That's also called a moment of inertia!
 
  • Haha
  • Like
Likes   Reactions: jbriggs444, haruspex and ergospherical
Ok I'll try
 
fabiancillo said:
$$I_x = \displaystyle\frac{bh^3}{12}$$
$$I_{xy} = \displaystyle\frac{b^2h^2}{24}$$
Fixed the LaTeX by doubling the dollar signs.
I note you only quote equations for a triangle. Do you have any for the rectangles? If not, you'll need to cut those into triangles.
Do you know the parallel axis theorem?
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
Replies
8
Views
12K
Replies
4
Views
4K
Replies
10
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K