Calculate PSI of Hollow Cube with Hole Opened

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The discussion focuses on calculating the psi of a hollow cube with a volume of 504 cm³ after a hole is opened, leading to a hollow cylinder. Initially, the cube contains air at 94 psi. Upon opening a hole with an area of 12.56 cm², the cylinder, which is 14 cm long with a radius of 2 cm, is confirmed to be a vacuum. Boyle's Law (PV = c) is identified as the primary method for calculating the new psi of the structure after the air is released.

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Suppose you have a hollow cube with a volume of 504c3. The inside of the cube has a psi of 94 and is just air. Now suppose that a hole opened in the bottom of this cube with an area of 12.56cm2 that leads to a hollow cylinder that is 14 cm long with a radius of 2cm. Now how would you go about calculating the psi of this whole structure after the hole is opened, the air is released and the volume has changed.
 
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Does the cylinder contain air at normal atmospheric pressure, or is it vacuum?
 
Nugatory said:
Does the cylinder contain air at normal atmospheric pressure, or is it vacuum?
The cylinder would have a vacuum inside it
 
daviddjh said:
The cylinder would have a vacuum inside it

OK - that makes it easy. Boyle's Law, ##PV=c## where ##c## is a constant, will get you an answer in short order.

(Boyle's Law would still get you there if the cylinder weren't a vacuum, but it would be more work).
 

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