Calculate Satellite Gain: Earth-to-Sphere Ratio

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SUMMARY

The discussion focuses on calculating the gain of a geosynchronous satellite relative to an isotropic antenna. The formula derived is based on the inverse ratio of the Earth's cross-sectional area to the surface area of a sphere at an altitude of 36,000 km. The correct representation of the Earth's cross-sectional area is πR², not 4πR², as the latter accounts for the entire sphere rather than just a slice through its center. This clarification is crucial for accurate gain calculations in satellite communications.

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bos1234
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This is not a connection. I just want ot know how they dervied this formula from gain

Consider a geosynchronous satellite whose global beam covers all of the visible Earth's surface. The radius of the Earth is about 6400km, and the altitude of the satellite is 36,000km.

How would you work out the gain of the satellite?

Book has :Satellite antenna gain, relative to the isotropic antenna situation, is equivalent to the inverse ratio of the cross-secitonal area of the Earth to the surface area of a sphere at 36,000km, assuming 100% effeciency.

Solution has \frac{4pi R^2}{pi R^2}

numerator is for satellite and denominator is for earth






The Attempt at a Solution


 
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hi bos1234! :smile:
bos1234 said:
Book has :Satellite antenna gain, relative to the isotropic antenna situation, is equivalent to the inverse ratio of the cross-secitonal area of the Earth to the surface area of a sphere at 36,000km, assuming 100% effeciency.

the cross-sectional area of the Earth isn't the area of the whole sphere, it's only the area of a slice through the centre of the sphere, so it's only πR2 instead of 4πR2 :wink:
 

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