Calculating Satellite Orbit Radius on the Moon

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SUMMARY

The discussion focuses on calculating the radius of a satellite's orbit around the Moon, given its gravitational field strength and altitude. The Moon's radius is 1.74 x 106 m, and the gravitational field strength is approximately 0.17 times that of Earth's. The satellite orbits at an altitude of 100 km above the Moon's surface. The relevant equation discussed is T2/R3 = 4π2/GM, although participants note the absence of specific values for period and mass, indicating a need for a more direct approach to the solution.

PREREQUISITES
  • Understanding of gravitational field strength and its relation to orbital mechanics
  • Familiarity with the formula T2/R3 = 4π2/GM
  • Basic knowledge of satellite motion and altitude effects
  • Ability to manipulate scientific notation and units of measurement
NEXT STEPS
  • Research the concept of gravitational field strength on celestial bodies
  • Learn how to derive orbital radius from gravitational parameters
  • Study the effects of altitude on satellite motion
  • Explore alternative methods for calculating orbital mechanics without period or mass
USEFUL FOR

Students studying physics, particularly those focusing on orbital mechanics and gravitational forces, as well as educators seeking to enhance their understanding of satellite dynamics around celestial bodies.

kim123
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Homework Statement


The gravitational field strength on the moon, which has a radius of 1.74 x 10^6 m, is
approximately 0.17 as large as the gravitational field strength at the surface of the earth. The satellite is at an altitude of 100km above the moon.

What is the radius of the orbit of the satellite?


Homework Equations


I thought I would use the T^2/R^3= 4pi^2/GM


The Attempt at a Solution


That's just the thing. There is no period or mass in the problem, so I'm not sure how to solve this.
 
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Re-read the question carefully. There may be a more direct path to the answer.
 

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