Calculate Tangential Speed of Yo-yo with Centripetal Acceleration of 289 m/s2

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The discussion focuses on calculating the tangential speed of a yo-yo given a centripetal acceleration of 289 m/s² and a string length of 0.78 m. The formula for centripetal acceleration, a = v²/r, is utilized, where v represents tangential speed and r is the radius. By rearranging the formula to solve for v, the tangential speed can be determined as v = √(a * r). Substituting the values, the tangential speed is calculated to be approximately 14.9 m/s.

PREREQUISITES
  • Understanding of centripetal acceleration
  • Familiarity with the formula a = v²/r
  • Basic algebra for rearranging equations
  • Knowledge of units of measurement in physics (m/s, m/s²)
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Trotsky
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Hello! Usually I have my friend help me with physics questions but he is away on vacation and I don't want to bother him. Anyways, the question is:

A young boy swings a yo-yo horizontally above his head so that the yo-yo has a centripetal acceleration of 289 m/s (squared).
If the yo-yo's string is .78 m long, what is the yo-yo's tangential speed? Answer in units of m/s.
 
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Do you know the formula for centripetal acceleration? It is
[tex]a=\frac{v^2}{r}[/tex]
v is the tangential speed and r is the radius.
 

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