Calculate Tension in String: m1=4.50 kg, m2=7.50 kg, a=1.4 m/s^2

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SUMMARY

The discussion focuses on calculating the tension in a string connecting two blocks with masses m1 = 4.50 kg and m2 = 7.50 kg, subjected to an acceleration of 1.4 m/s². The setup involves a frictionless pulley and frictionless inclines. Participants emphasize the importance of drawing free-body diagrams for each block to identify forces acting on them. The equation used to find the tension is Tension - m1 * g * sin(35°) = m1 * a.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of free-body diagrams
  • Familiarity with trigonometric functions, specifically sine
  • Basic principles of pulley systems
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  • Study the application of Newton's laws in multi-body systems
  • Learn how to draw and analyze free-body diagrams
  • Explore the effects of friction in pulley systems
  • Investigate the role of angles in tension calculations
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Homework Statement


Two blocks of mass m1 = 4.50 kg and m2 = 7.50 kg are connected by a massless string that passes over a frictionless pulley.The inclines are frictionless.

p4-54alt.gif



the magnitude of acceleration of each block is 1.4 m/s^2


Find the tension in the string.
?_?
may someone help me start this problem
 
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Start by drawing a free-body diagram for each block.
Identify the forces and directions of each force on blocks 1 and 2 separately.
Then do you know how to find the tension?
 
yeah i tried that. thanks
i figured out the problem

sum of the force = Tension- M G sin 35 = M A
 

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