Calculate the amount of torque and power needed on an inclined plane

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To calculate the torque and power needed to move a car uphill on a 30-degree incline, the force equation is established as f - mgsin(30) = ma, ignoring friction. The acceleration is derived from the equation vf = vi + at, leading to a = v/10. The discussion emphasizes the need to express the force in terms of torque and total work done. Participants are encouraged to clarify relevant equations related to torque and power. The calculations aim to determine the necessary parameters to achieve a specified final velocity within 10 seconds.
babol2728
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Homework Statement
Calculate the amount of torque and power needed to move a car uphill
from rest on a 30-degree inclination and reach a certain final velocity in time
less than 10 seconds
Relevant Equations
car wheel radius = r
mass of car = m
initial velocity = 0
final velocity = v

Torque = Force x Radius
Power = Work/time = Force x Velocity = Torque x Angular Velocity
I have calculated the force equation on the x-plane which is f - mgsin(30) - friction force = ma
and from the equation vf = vi + at resulting a = v/10
 
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babol2728 said:
Homework Statement:: Calculate the amount of torque and power needed to move a car uphill
from rest on a 30-degree inclination and reach a certain final velocity in time
less than 10 seconds
Relevant Equations:: State in variables

Calculate the amount of torque and power needed to move a car uphill
from rest on a 30-degree inclination and reach a certain final velocity in time
less than 10 seconds
Per forum rules (Homework Help Guidelines for Students and Helpers) you must show some attempt.
Please also try to complete the Relevant Equations section. What equations have you been taught in connection with torque and power?
 
haruspex said:
Per forum rules (Homework Help Guidelines for Students and Helpers) you must show some attempt.
Please also try to complete the Relevant Equations section. What equations have you been taught in connection with torque and power?
I have corrected my post
 
babol2728 said:
I have calculated the force equation on the x-plane which is f - mgsin(30) - friction force = ma
and from the equation vf = vi + at resulting a = v/10
You are not told anything about friction, so ignore that.
From the above you can get an expression for the force. What torque does that lead to?
What total work is done?
 
Thread 'Chain falling out of a horizontal tube onto a table'
My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

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