Calculate the area of the circle

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Homework Help Overview

The problem involves calculating the area of a circle, with specific reference to certain line segments and angles related to the circle's geometry.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the interpretation of given values as lengths of line segments and explore the relationship between these segments and the circle's radius and diameter. There are suggestions to use trigonometric relationships and right triangles to express these dimensions.

Discussion Status

The discussion is active, with participants sharing different approaches to the problem. Some guidance has been offered regarding the use of triangles and angles, while others express a preference for simpler methods, indicating a variety of perspectives on how to tackle the problem.

Contextual Notes

There is a mention of a diagram linked in the thread, which may contain relevant information for solving the problem. Participants are encouraged to show their work, indicating a focus on the learning process rather than just the answer.

Saeed.z
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i tried hard to solve this question but i got a complicated answer

any hint ?

http://www.gulfup.net/uploads/13634557771.gif

thanks
 
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Saeed.z said:
i tried hard to solve this question but i got a complicated answer

any hint ?

http://www.gulfup.net/uploads/13634557771.gif

thanks

Show your work.

Anyway, what are the '2' and the '6': are they lengths of line segments, or are they areas of sub-regions?
 
^

yes, they are length of line segments.
 
Label the acute angle θ. Using the right triangle on the bottom, express the radius in terms of θ. Draw a line from the intersection of the secant with the circle arc, running to the intersection of the vertical diameter with the circle arc. This produces another right triangle, with the diameter as its hypotenuse. Express the diameter 2r in terms of θ using this larger triangle.

Chet
 
Chestermiller said:
Label the acute angle θ. Using the right triangle on the bottom, express the radius in terms of θ. Draw a line from the intersection of the secant with the circle arc, running to the intersection of the vertical diameter with the circle arc. This produces another right triangle, with the diameter as its hypotenuse. Express the diameter 2r in terms of θ using this larger triangle.

Chet

Well, I'll take your word for it that that would work, but you sure do like to make things difficult. There is no need to bring angles or trig into it at all. Pythagoras would have gotten this one right off and I don't think he knew any trig.

EDIT: "no need for angles" isn't quite right, since it DOES depend on similar triangles
 
Last edited:
I like your way better, although it gives the same answer.

Chet
 

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