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Calculate the average force on the ball during contact

  • Thread starter dylan61990
  • Start date
1. Homework Statement
A .145 kg pitched baseball moving at 35 m/s strikes a bat and is popped straight up (forming a 90 degree angle)to a height of 55.6 m before turning around. If the contact time is .50 seconds. calculate the average force on the ball during contact.


2. Homework Equations
p=mv
impulse=ft
m1v1+m2v2 = m1v1 prime +m2v2 prime
delta ft= delta mv


3. The Attempt at a Solution
I honestly have no idea but this is what i did
f=mv/t=.145(35 m/s)/.50 s= 10.15 N
 
Last edited:

Answers and Replies

Hootenanny
Staff Emeritus
Science Advisor
Gold Member
9,598
6
Hi Dylan and welcome to the Forums,

Could you post your attempt at answering the question please?
 
the answer in the book says that it is 1.4 times 10 to the 4 newtons, 43.3 degrees.

I just don't know how they got that, or what the degrees mean.
 
Hootenanny
Staff Emeritus
Science Advisor
Gold Member
9,598
6
Okay, lets take this one step at a time. If you thew a ball straight up from ground level, what would be the minimum velocity required such that it reached a maximum height of 55.6m?
 

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