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Calculate the average force on the ball during contact

  1. Jan 7, 2007 #1
    1. The problem statement, all variables and given/known data
    A .145 kg pitched baseball moving at 35 m/s strikes a bat and is popped straight up (forming a 90 degree angle)to a height of 55.6 m before turning around. If the contact time is .50 seconds. calculate the average force on the ball during contact.


    2. Relevant equations
    p=mv
    impulse=ft
    m1v1+m2v2 = m1v1 prime +m2v2 prime
    delta ft= delta mv


    3. The attempt at a solution
    I honestly have no idea but this is what i did
    f=mv/t=.145(35 m/s)/.50 s= 10.15 N
     
    Last edited: Jan 7, 2007
  2. jcsd
  3. Jan 7, 2007 #2

    Hootenanny

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    Hi Dylan and welcome to the Forums,

    Could you post your attempt at answering the question please?
     
  4. Jan 7, 2007 #3
    the answer in the book says that it is 1.4 times 10 to the 4 newtons, 43.3 degrees.

    I just don't know how they got that, or what the degrees mean.
     
  5. Jan 8, 2007 #4

    Hootenanny

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    Okay, lets take this one step at a time. If you thew a ball straight up from ground level, what would be the minimum velocity required such that it reached a maximum height of 55.6m?
     
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