What Is the Average Force of Impact on a Ball Struck by a Bat?

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SUMMARY

The average force of impact on a ball struck by a bat, given a mass of 0.2 kg and an initial speed of 26 m/s, is calculated using the formula F = Δp/Δt. The correct average force is determined to be 5200 N, although the initial calculation was off by a factor of two. Additionally, when the average force is 20000 N, the resulting speed after the collision is -74 m/s, indicating a reversal of direction.

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  • Understanding of Newton's Second Law (F = ma)
  • Familiarity with impulse-momentum theorem (Fnett = Δp)
  • Basic knowledge of kinematics equations
  • Ability to perform unit conversions and calculations involving mass and velocity
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  • Learn about kinematics equations and their applications in collision scenarios
  • Explore advanced topics in dynamics, including force analysis during collisions
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Homework Statement



A ball with a mass of .2 kg traveling at a speed of 26 m/s is struck by a bat. If the duration of the impulse is .001 seconds and the speed of the ball afterwards is the same as before, what is the average force (to the nearest Newton) of the impact? On the other hand, if the magnitude of the average force is 20000 N, what is the speed to the nearest m/s after collision?

Homework Equations



Fnett =\Deltap = m\Deltav

The Attempt at a Solution



F=(.2 kg)(26m/s-0)/.001 = 5200

This answer is always 1/2 off the correct answer so I'm not sure if the equation I'm using is wrong or if I'm applying it incorrectly. As for the second question, I'm not quite sure where to go with it.
 
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Haha I got the answer. It goes back to thinking Kinematics equations where vf=vi+at

therefore, to get the acceleration you use Newton's second law: F=ma where F= 20000N and m = .2 to get a = 100,000

vf = vi + at
vf= 26 - (100,000)(.001)
vf = -74 m/s
vf is 74 m/s in the opposite direction it was thrown in

hope this helps someone else that's stuck
 

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