1. The problem statement, all variables and given/known data Baseball(0.145kg) pitch is pitched horizontally at 32m/s, ball pops straight up to a height of 36.5m. If the contact time between bat and ball is 2.5ms, calculate the average force between the ball and the batt during contact. 2. Relevant equations Favg = Δp/t KE=KE 3. The attempt at a solution 1/2mv^2 = mgh v= squar(2gh) Find Vo when ball leaves bat ((0.145kg*27m/s)-(0.145kg*32m/s))/Tcontact = -290 N My answer is wrong, in my solution manual it breaks the variables up into x and y. Then it uses Pythagoras equation for the hypotenus. Is that okay to do for forces? i thought that was only used for velocity vectors or.. Ima little confused.