Mrs. K has just received a large shipment of candy at the local Blockbuster. Wanting to get out of the store as fast as possible (so that she can return to her loving husband) she uses the shrink wrap machine to bundle the candy into two blocks, one of 8 kg and the other of 2 kg. The 8 kg bundle is 4 m in length and the 2 kg bundle is only 20 cm in length. She places the smaller bundle on the 8 kg bundle such that the front faces of both are flush with each other. She pushes on the 8 kg bundle with a constant force of 100 N and the system begins to move. The coefficient of friction between the 8 kg bundle and the floor is only 0.1. She notices that as she pushes on the candy that the 2 kg bundle is slowly drifting towards her. When she has pushed a total distance of 10 m, the 2 kg bundle has moved so that it is now flush with the rear of the 8 kg block. Calculate the coefficient of friction between the two bundles of candy.
There is a constant force being applied, thereforre work is being done.
W = Fcosd
The Attempt at a Solution
I can calculate the work being done by the person on the entire system.
W= 100N(cos0)(10m) = 1000J.
As well work being done by friction on the system
W = (0.1)(100N)(cos180)(10m) = -100J
I am not sure where to go from here.
The work done by friction on the 2kg box, I could then figure out the coefficient of friction, knowing the force of friction and Fn. But other then that I dont know where to go....
Any help is appreciated thank you.