Calculate the conductivity σ of the material of which this wire is made

[mh53eflyguy]

A wire is 1.0 m long and 1.1 mm2 in cross-sectional area. It carries a current of 5.4 A when a 2.1 V potential difference is applied between its ends. Calculate the conductivity σ of the material of which this wire is made.

Known data: I hate Wileyplus.

Ok, REAL known data: I know that I have to use 2pi(r), and pi(r)^2

R= (roe)(L)/(A)


I understand that if I were to use a specific material, I could find the resistance. However, this does not ask for that. Please help!

 

[LowlyPion]

Welcome to PF.

You know the resistance from V/I.

You know the A.

You know the Length.

So what is σ?

σ = 1/ρ
and
R = ρL/A

 

[nlightner]

Hello,

Thank you for your question. To calculate the conductivity (σ) of the material of which the wire is made, we can use the formula σ = I/(AΔV), where I is the current, A is the cross-sectional area, and ΔV is the potential difference.

In this case, we have a wire that is 1.0 m long and has a cross-sectional area of 1.1 mm^2. It is carrying a current of 5.4 A when a potential difference of 2.1 V is applied. Plugging these values into the formula, we get:

σ = (5.4 A)/(1.1 mm^2 * 0.0021 V)

= 2.44 x 10^6 A/m

This means that the conductivity of the material of the wire is 2.44 x 10^6 A/m. I hope this helps clarify things for you. Let me know if you have any other questions. Thank you.