Calculate the Depth of a Well: u, a and Time Given

  • Thread starter Thread starter milto
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Homework Help Overview

The discussion revolves around calculating the depth of a well, given the time it takes for a stone to hit the bottom and the time taken for the sound to travel back. The problem involves concepts from kinematics and sound propagation.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the equations relevant to the problem, including the relationship between depth, time, and speed of sound. There is uncertainty regarding the correct application of these equations.

Discussion Status

Some participants have attempted calculations based on suggested equations, while others express uncertainty about the results. There is no explicit consensus on the correctness of the calculations provided.

Contextual Notes

The original poster notes confusion regarding the equations due to the pace of instruction in class. There is also a distinction made between the time taken for the stone to fall and the time taken for the sound to return.

milto
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Homework Statement



How deep is the well remember its takes him 3.8 seconds to hear the stone hit the bottom not 3.8 to see it hit the bottom.
u=0ms^-1
a=10ms^-2


Homework Equations



Not 100% sure what equations to use because my teacher goes to quickly

The Attempt at a Solution



Would you be able to show me the equations to use to solve it.
Thanks Nick.
 
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Try these

Depth = InitialSpeed*DropTime + 0.5*Acceleration*DropTime²

SpeedOfSound = Depth/EchoTime

TotalTime = DropTime + EchoTime
 
Thanks mate, I got 35.28m for the depth of the well, is that correct??
 
Dunno mate! I didn't get that far.
 

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