Calculate the eigenvectors of a specific matrix

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SUMMARY

The discussion centers on calculating the eigenvectors of the matrix A, defined as follows: A = [[2, 1, 0, 1], [0, 3, -1, 0], [0, 1, 1, 0], [0, -1, 0, 3]]. The eigenvalues identified are λ1=2 with multiplicity 3 and λ2=3 with multiplicity 1. The eigenvectors provided include [-1, -1, -1, -1], [0, 1, 2, 0], and [1, 0, 0, 0]. A critical point raised is the confusion regarding the first eigenvector being zero, which is clarified by noting that there exists a nonzero eigenvector corresponding to the eigenvalue 2.

PREREQUISITES
  • Understanding of eigenvalues and eigenvectors
  • Familiarity with matrix operations, specifically matrix subtraction and solving linear equations
  • Knowledge of linear algebra concepts, particularly multiplicity of eigenvalues
  • Basic understanding of differential equations
NEXT STEPS
  • Review the process of calculating eigenvalues and eigenvectors using the characteristic polynomial
  • Study the implications of eigenvalue multiplicity on the eigenvector calculation
  • Learn how to apply eigenvectors in solving differential equations
  • Explore matrix diagonalization techniques and their applications
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Students and professionals in mathematics, particularly those studying linear algebra and its applications in differential equations, as well as anyone needing to calculate eigenvectors for specific matrices.

Dassinia
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Hello,
I'm really having a problem to calculate the eigenvectors of a specific matrix, I'm used to do this but i don't know why I'm stuck at this one

Homework Statement



A=
2 1 0 1
0 3 -1 0
0 1 1 0
0 -1 0 3

λ1=2 multiplicity 3
λ2=3 multiplicity 1

A-2I=
0 1 0 1
0 1 -1 0
0 1 -1 0
0 -1 0 1

The eigenvectors are given
[-1 -1 -1 -1]
[0 1 2 0]
[1 0 0 0]

If I solve
(A-2I)xi=0
I have
x1=0
x2+x4=0
x2-x3=0
-x2+x4=0


I have to use this for differential equations, and my linear algebra course is far behind, I don't remember what I'm supposed to do when we get the first eigenvector =0, because when the multiplicity of the eigenvalue is > 0 we use the first one to find the following eigenvectors

Thanks!
 
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Dassinia said:
Hello,
I'm really having a problem to calculate the eigenvectors of a specific matrix, I'm used to do this but i don't know why I'm stuck at this one

Homework Statement



A=
2 1 0 1
0 3 -1 0
0 1 1 0
0 -1 0 3

λ1=2 multiplicity 3
λ2=3 multiplicity 1

A-2I=
0 1 0 1
0 1 -1 0
0 1 -1 0
0 -1 0 1

The eigenvectors are given
[-1 -1 -1 -1]
[0 1 2 0]
[1 0 0 0]

If I solve
(A-2I)xi=0
I have
x1=0
x2+x4=0
x2-x3=0
-x2+x4=0


I have to use this for differential equations, and my linear algebra course is far behind, I don't remember what I'm supposed to do when we get the first eigenvector =0, because when the multiplicity of the eigenvalue is > 0 we use the first one to find the following eigenvectors

Thanks!

There is a nonzero eigenvector corresponding to eigenvalue 2. Rethink your conclusion that solving that matrix gives you x1=0.
 

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