Calculate the Force between Charges

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SUMMARY

The discussion focuses on calculating the force between two point charges using Coulomb's Law. The charges involved are 5 microcoulombs and 6 microcoulombs, located at coordinates (1,2,3) and (5,-2,4) respectively. The distance vector between the charges is determined to be 4i - 4j + k, with a magnitude of approximately 5.744. The force is calculated using the formula F = k*q1*q2/d^2, where k is Coulomb's constant (9 x 10^9 N m²/C²), leading to a force magnitude of 0.27 N.

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Homework Statement



Find the magnitude of the force b/w charges

(1,2,3) (5,-2,4)

() ()
5 micro Columb 6 micro columb
charge 1 charge 2

The Attempt at a Solution





Vector r = (5-1)i + (-2-2)j + (4-3)k
Vector r = 4i -4j + k

Magnitude of Vector r = Square root (4^2 + (-4)^2 + 1^2)

Magnitude of Vector r = square root (33) or 5.744


a/c to columbs law

F= (9x10^9) (5x10^-6 ) (6x10^ -6 ) (4i-4j+k)
5.744 ^3 (cube b/c unit vector )

F= 0.27 { what should i do of ( 4i-4j+k )
5.744^3


what should i do please i hve got paper on WeDnesday Help me
 
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Hi wizard.ubit, welcome to PF.
In the problem only magnitude is required.
So F = k*q1*q2/d^2
 

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