Calculating Electric Field and Force Between Charged Rings

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SUMMARY

The discussion focuses on calculating the electric field and force between two charged rings, specifically a left ring charged to -17 nC and a right ring charged to +17 nC, positioned 25 cm apart. The electric field at the midpoint is derived using the equation E1 = ZQ1/(4πε0(z^2 + r^2)^(3/2)). The user initially calculated the electric field as 2.2E4 but received feedback indicating a mismatch in the variables z and r. Correctly identifying these variables is crucial for accurate calculations.

PREREQUISITES
  • Understanding of electric fields and forces between charged objects
  • Familiarity with Coulomb's law and its applications
  • Knowledge of the equation for electric fields due to point charges
  • Basic algebra and unit conversion skills
NEXT STEPS
  • Review the derivation and application of the electric field equation E1 = ZQ1/(4πε0(z^2 + r^2)^(3/2))
  • Practice calculating electric fields for different configurations of charged objects
  • Explore the concept of superposition in electric fields
  • Learn about the implications of charge distribution on electric field strength
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Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields and forces in charged systems.

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Homework Statement


Two 10-cm-diameter charged rings face each other, 25cm apart. The left ring is charged to -17nC and the right ring is charged to +17nC .
A.What is the magnitude of the electric field E⃗ at the midpoint between the two rings?B.What is the magnitude of the force F⃗ on a -1.0 nC charge placed at the midpoint?
Express your answer to two significant figures and include the appropriate units.

Homework Equations


(E1)z=ZQ1/4πε0(z^2+r^2)^(3/2)

The Attempt at a Solution


((9E9)(.10)(-17E-9))/((.10)^2+(.50)^2)^3/2= 2.2E4.
Unfortunately
this is not the answer any help?
 
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You don't seem to have correctly matched up the z and r variables in the equation to the given numbers. What values for z and r have you used?
 

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