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timeforplanb
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Homework Statement
Calculate the fundamental frequency of a steel rod of length 2.00 m. What is the next possible standing wave frequency of this rod? Where should the rod be clamped to excite a standing wave of this frequency?
Homework Equations
Fn=nv/2L
The Attempt at a Solution
since the velocity of sound in steel was needed and it wasn't mentioned in the problem, i figured that i had to search for the value myself. i got the value of 6100 m/s.
for the fundamental frequency:
F1=(v/2L)
F1=((6100m/s)/(2x2m))
F1=1525 Hz
for the next standing wave frequency:
for the fundamental frequency:
F1=(2v/2L)
F1=((2x6100m/s)/(2x2m))
F1=3050 Hz
about the third problem though, i have no idea how to solve it.
the length of the rod could be determined by the equation L=λ/2 (λ=wavelength) when the clamp is at the center of the rod, right? what happens then if we move the clamp to another position? will there be a change in the wavelength or other parameters? more importantly, can anyone provide the equation needed to answer the third question? thank you very much.
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