Calculate the initial velocity of the elevator

In summary, an elevator of mass 290kg is uniformly decelerated to rest over a distance of 4m by a cable in which the tension is 3631N. The acceleration due to gravity is 9.8m/s^2. Calculate the initial velocity of the elevator at the beginning of the 4m descent. Answer in units of m/s.
  • #36
the student exerts

X=5.98*10^24 * A
 
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  • #37
does X in this also equal 637N
 
  • #38
anglum said:
does X in this also equal 637N

exactly.
 
  • #39
so then i solve it as 637/5.98*10^24 = A

A = 1.065217 *10^-22
 
  • #40
awesome... thank you soooooo much for all your help tonite... u are a very patient man and a very good teacher
 
  • #41
anglum said:
awesome... thank you soooooo much for all your help tonite... u are a very patient man and a very good teacher

:smile: you're welcome. glad to help. keep at it! you're doing well!
 

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