Calculate the magnetic field from the vector potential

Click For Summary
The discussion revolves around deriving the axial magnetic field from the magnetic vector potential of a current-carrying loop, with the user successfully deriving the radial field but struggling with the axial field. The user identifies a mismatch in coefficients between their equations and suspects that treating certain variables as constants may be the source of the error. A response highlights potential typographical errors in the equations, specifically regarding the denominators, which could be causing the discrepancies. The user acknowledges the typographical error and plans to update their equations and provide a complete derivation for the axial field. This exchange emphasizes the importance of accuracy in mathematical derivations and peer feedback in problem-solving.
arjun_ar
Messages
3
Reaction score
4
Homework Statement
Given the magnetic vector potential of a current carrying loop in cylindrical coordinate system, derive the axial and radial magnetic fields.
Relevant Equations
Please read ahead.
I am trying to derive radial and axial magnetic fields of a current carrying loop from its magnetic vector potential. So far, I have succeeded in deriving the radial field but axial field derivation gives me trouble.
Z2N67kE.png


My derivation of radial field (eq 1) can be found here.

Can anyone point out where I went wrong in the derivation of axial field?

My derivation of axial field is given below.

EjnkUB1.png


In case the images are blurred, you can see them here and here.

On comparing, Eq.7 with Eq.2, the coefficient of E do not match.

I have done this derivation multiple times, yet arrive at the same answer.
Can anyone point me where I went wrong?
 
Last edited:
Physics news on Phys.org
Hmm is it dead sure that K and E are independent of ##\rho,z##? So you can treat them as constants when taking the derivatives with respect to those variables?
 
I think the mistake is here:

1658095752159.png


The two expressions circled in green are not equivalent.

-----------------------------------------------------------------------

Do you have typographical errors in your equations (1) and (2)? Should the denominators inside the square brackets be ##(a-\rho)^2 + z^2## instead of ##(a+\rho)^2 + z^2##?
 
  • Like
  • Informative
Likes arjun_ar and Delta2
Delta2 said:
Hmm is it dead sure that K and E are independent of ##\rho,z##? So you can treat them as constants when taking the derivatives with respect to those variables?
Thank you for your response.
I think they are independent of ##\rho,z##. In my derivation of radial field, I have treated them to be independent of ##z## and arrived at the exact solution.
 
TSny said:
I think the mistake is here:

View attachment 304311

The two expressions circled in green are not equivalent.

-----------------------------------------------------------------------

Do you have typographical errors in your equations (1) and (2)? Should the denominators inside the square brackets be ##(a-\rho)^2 + z^2## instead of ##(a+\rho)^2 + z^2##?
Thank you! This solves my problem. I don't know how I missed it!

There is indeed a typographical error for equations (1) and (2). I will update them and provide a full derivation for axial field asap.
 
  • Like
Likes TSny and Delta2
I want to find the solution to the integral ##\theta = \int_0^{\theta}\frac{du}{\sqrt{(c-u^2 +2u^3)}}## I can see that ##\frac{d^2u}{d\theta^2} = A +Bu+Cu^2## is a Weierstrass elliptic function, which can be generated from ##\Large(\normalsize\frac{du}{d\theta}\Large)\normalsize^2 = c-u^2 +2u^3## (A = 0, B=-1, C=3) So does this make my integral an elliptic integral? I haven't been able to find a table of integrals anywhere which contains an integral of this form so I'm a bit stuck. TerryW

Similar threads

Replies
12
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
19
Views
2K
Replies
44
Views
5K
  • · Replies 1 ·
Replies
1
Views
464
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K