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Calculate the magnitude and direction of the net electric force

  • Thread starter crybllrd
  • Start date
  • #1
120
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Homework Statement



Three point charges lie along a straight line as shown in the figure below, where q1 = 6.60 µC, q2 = 1.41 µC, and q3 = -1.9 µC. The separation distances are d1 = 3.00 cm and d2 = 2.00 cm. Calculate the magnitude and direction of the net electric force on each of the charges.

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I need to state the magnitudes and directions of all 3 charges.

Homework Equations



[itex]F_{e}=k_{e}\frac{|q_{1}||q_{2}|}{r^{2}}[/itex]

The Attempt at a Solution




I have to convert the values to be able to properly use the equations.
q1=6.60e-9 C
q2=1.41e-9 C
q3=-1.9e-9 C
d1=.03 m
d2=.02 m
k=8.9876e9

I think I will only need help with the first part, I then should be able to do the rest on my own.
between q1 and q2:
[itex]F_{e}=(8.9876e9)\frac{|6.60e-9||1.41e-9|}{.03^{2}}=9.29e-5[/itex]to the left

between q1 and q3:
[itex]F_{e}=(8.9876e9)\frac{|6.60e-9||-1.9e-9|}{.05^{2}}=4.51e-5[/itex] to the right

I will now subtract the answers: (9.29e-5)-(4.51e-5)=4.78e-5
The force to the left is greater than the force to the right, so it will move to the left.

When I put this answer it says "Your response differs significantly from the correct answer."
The to the left part is obviously right.

What did I do wrong here?
 

Answers and Replies

  • #2
Doc Al
Mentor
44,872
1,120
I have to convert the values to be able to properly use the equations.
q1=6.60e-9 C
q2=1.41e-9 C
q3=-1.9e-9 C
I haven't looked at the rest of your work, but these are not quite right. Realize that μ means 10-6, not 10-9.
 
  • #3
120
0
Thanks a lot, I did have the conversions wrong.
I re worked it out and came up with the correct answer of 47.8 to the left.
Thanks again.
 

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