Calculate the magnitude of the average net force on the car

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SUMMARY

The discussion focuses on calculating the average net force acting on a 1270-kg car that slows down from 18.1 m/s to 11.3 m/s over a distance of 28.4 m on a sandy surface. The work-energy principle is applied, using the equation W = F(delta r)(cos theta), where the initial kinetic energy is converted into work done against friction. The net work done on the car is negative, indicating that the force exerted by friction is greater than the driving force, resulting in a deceleration of the vehicle.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the work-energy principle
  • Knowledge of kinetic energy calculations
  • Basic algebra for solving equations
NEXT STEPS
  • Calculate the work done on the car using the work-energy principle
  • Explore the implications of negative work on vehicle dynamics
  • Learn about frictional forces and their impact on motion
  • Investigate different surfaces and their effects on vehicle speed
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of the work-energy principle in action.

Chrisleo13
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Homework Statement



A 1270-kg car coasts on a horizontal road with a speed of 18.1 m/s. After crossing an unpaved, sandy stretch of road 28.4 m long, its speed decreases to 11.3 m/s. Was the net work done on the car positive, negative, or zero?

b. Calculate the magnitude of the average net force on the car in the sandy section.


Homework Equations


W = F(delta r)(cos theta)


The Attempt at a Solution


I started looking at it. I understand work but for some reason I am stuck here.
 
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Well look at it this way, initially you consider all of its energy to be kinetic. Once it begins to cross the sand, some of it's kinetic energy is transcribed into work:

\frac{1}{2}mv_1^2 = \frac{1}{2}mv_2^2 + F\Delta d

Mass remains constant, and we are told that v_2 decreases, that implies that work; F\Delta d is positive (or else the equation would not be balanced).

For part b) you just need to solve the equation listed above. You have everything except F.
 
Alright, I got it. Thanks.
 

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