Calculate the mass of ice with heat transfer / latent heat

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The discussion centers on calculating the initial mass of ice (mi) in a heat transfer problem involving ice and a solid object. The initial temperature of the ice is -20°C, while the solid's temperature is 35°C, and the final equilibrium temperature is 10°C. Key equations for heat transfer, including Q=mcΔT and Q=ml, are applied, but the user struggles with the next steps after calculating the heat lost by the solid. Clarification is sought regarding the initial and final conditions of the system, emphasizing the need to determine the initial mass of ice before the solid was placed on it. The final answer is noted to be mi = 0.100 kg.
adam640
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Homework Statement



Find mi, the initial mass of ice.

Ti = -20
ci = 2093Jkg-1K-1
Ts = +35
ms = 2kg
cs = 837.4Jkg-1K-1
cw = 4187Jkg-1K-1
lf = 3.35x105Jkg-1

S = solid
W = water
I = ice
lf = latent heat of fusion of ice / water

Homework Equations


Q=mc\DeltaT
Q=C\DeltaT
Q=ml

The Attempt at a Solution


For the Solid
Qs = (2)(837.4)(10-35)
Qs = -4.187x104J

For the Water / Ice
Qi = mix(4.186x104)
Q = mix(3.35x105)
Qw = mix(4.187x104)

I don't know where to go from here, I have seen the markscheme however and I am aware that the answer is: mi = 0.100kg
 
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You've specified everything but the experimental circumstances. What are the initial and final conditions? Do you want to calculate the mass of ice remaining, or the initial mass of ice?
 
Oops, the Solid is placed on top of the ice. The ice then melts and the final temperature of both the solid and the ice is 10. So basically I'm looking for the initial mass of the ice, before the rock was placed onto it.
 
So, the final temperature is 10C. What does that tell you about the the water in the system?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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