Calculate the mass of the disk?

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Homework Help Overview

The discussion revolves around calculating the mass of a disk in a system where a piece of clay is attached to it. The moment of inertia of the disk-clay system is provided, along with the mass of the clay. Participants are exploring the relationship between the moment of inertia and the individual masses of the disk and clay.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the possibility of summing the individual moments of inertia of the disk and clay. There is uncertainty regarding the correct interpretation of the axis of rotation and the radius values needed for calculations. Some participants question whether a diagram is available to clarify the setup.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the problem setup and the necessary parameters for calculating the mass of the disk. There is a focus on ensuring that all relevant information is considered before proceeding with calculations.

Contextual Notes

Participants note that the radius of the disk and the clay is not provided, which is essential for determining the moment of inertia. The original poster has indicated that the clay is positioned at the rim of the disk, which may influence the calculations.

alaa amed
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Homework Statement


The moment of inertia of the disk-clay system about the central axis of the disk is I = 1.5 kg m2
Disk's mass = M
The clay's mass = 0.12 kg
Calculate the mass of the disk?

Homework Equations


I = m r^2

The Attempt at a Solution


I thought that the moment of inertia may just be the sum of the individual moment of inertia's of the two objects. I know that I for a disk is equal to 1/4 MR^2, but I do not know the one for the clay.[/B]
 
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I thought that the moment of inertia may just be the sum of the individual moment of inertia's of the two objects.
Correct.

I know that I for a disk is equal to 1/4 MR^2, but I do not know the one for the clay.

You sure you've interpreted the axis correctly?
https://en.wikipedia.org/wiki/List_of_moments_of_inertia

Was there a diagram? As it is, we don't know r disk or rclay so can't find mclay.
 
billy_joule said:
Correct.



You sure you've interpreted the axis correctly?
https://en.wikipedia.org/wiki/List_of_moments_of_inertia

Was there a diagram? As it is, we don't know r disk or rclay so can't find mclay.
Yes. The diagram showed a piece of clay is sitting at the rim of the disk and not sliding on the disk.
 
Post the diagram and the entire question statement word for word, without it we're just guessing/relying on your interpretation.
 
upload_2016-6-9_1-36-57.png


A horizontal uniform disk with a mass M and a radius R=1.5m is free to rotate about its central axis perpendicular to the disk’s flat surface. A piece of clay with a mass m=0.12kg is sitting at the rim of the disk and does not slide on the disk. The moment of inertia of the disk-clay system about the central axis of the disk is I=1.5kgm2.At time t=0s, a constant external force, F, is applied tangentially at the rim of the disk causing the disk-clay system, initially at rest, to start rotating with a constant angular acceleration ofα=0.25rad/s2.
 
There's doesn't appear to be a question?
Can you follow the link in post #2 and identify the relevant MOI equations for the disk and clay?
 
alaa amed said:
perpendicular to the disk’s flat surface
Note that part of the axis specification.
 

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