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Calculate the maximum height of ball 1

  1. Dec 21, 2008 #1
    1. The problem statement, all variables and given/known data
    Two balls are connected by a string that stretches over a massless, frictionless pulley. Ball 1 has a mass of 0.45 kg and is held 0.74 m above the ground. Ball 2 has a mass of 5.7 kg and is held 0.88 m above the ground. When the balls are released, ball 2 falls to the ground, looses 30 % of its kinetic energy and rebounds to some maximum rebound height. When the balls are released, ball 1 travels to some maximum height before starting to fall. Assume that ball 1 reaches its maximum height during ball 2's rebound so that the string doesn't pull.
    Calculate the maximum height of ball 1 from and ground and the rebound height of ball 2.

    2. Relevant equations

    3. The attempt at a solution
    can you check my work i am stuck
    I would calculate the kinetic energy of ball 2 just before and after it hits the ground, using
    Just before impact, ball 2 (M) and ball 1 (m) have acquired kinetic energy
    (1/2)mV^2 + (1/2)MV^2
    = M g*0.74 - m g*0.74 Solve for V of both balls, and the kinetic energy of ball 2.

    (1/2)(m + M)V^2 = 0.74 (M-m)g
    V^2 = [(M-m)/(M+m)]g*1.48 = 12.38 m^2/s^2
    V = 3.52 m/s

    = After impact, ball 2 will have 70% of the pre-impact kinetic energy, and its velocity will be V' = sqrt(0.7)V= 0.8367V = 2.94 m/s
    Right after ball 2's impact, Ball 1 will continue to rise for a while because it suffered no impact and maintained its velocity V when ball 2 hits the ground. There will be no tension in the string while ball 2 and ba1l 1 both rise.
    Ball 1 rises a distance H1 given by
    M g H1 = (1/2) M V'^2 = (1/2)M(0.7)V^2
    H1 = (0.7)V^2/(2g) = 0.35 V^2/g

    When ball 1 hits the ground, ball 2 has already risen from 0.74 to 0.74 + 0.88 = 1.62 m above the ground. It will rise an additional distance until its kinetic energy (1/2) mV^2(at impact)is converted to potential energy
  2. jcsd
  3. Dec 22, 2008 #2


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    Hi myoplex11! :smile:

    Looks good down to …
    … where you should still be using V = 3.52 (not 0.7V) :wink:

    (are you mixing up ball 1 and 2?)

    Apart from that, everything's fine.

    What are you getting for the maximum and rebound heights? :smile:
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