Calculate the net force acting on the object in the diagram

AI Thread Summary
To calculate the net force in Diagram B, the Sine and Cosine Laws are applied, resulting in a net force of 16 N at an angle of 49 degrees west of north. The discussion highlights confusion regarding the calculations and suggests using vector decomposition as a simpler method for finding the net force. By breaking down each force into its x and y components and summing them, the resultant force can be determined more easily. The example provided illustrates how to convert forces into components for clearer analysis. Understanding these concepts is crucial for accurately solving problems involving net forces.
roguekiller93
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Homework Statement


Calculate the net force in Diagram B.

Homework Equations


Sine Law: sin a/a = sin b/b = sin c/ c
Cosine Law: c^2 = a^2 + b^2 -2ab*cos(c)

The Attempt at a Solution


c^2 = (2N)^2 + (17)^2 -2(2)(17)*cos(45)
= 16 N
sin b/ 17N = sin45/16N
= 49 degrees

Fnet = 16 N (W 49 degrees N)

I am really confused with this unit. I don't know if I did it right, but I would appreciate feedback on where and how i went wrong.[/B]
diagrams-png.59601.png
 
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roguekiller93 said:

Homework Statement


Calculate the net force in Diagram B.

Homework Equations


Sine Law: sin a/a = sin b/b = sin c/ c
Cosine Law: c^2 = a^2 + b^2 -2ab*cos(c)

The Attempt at a Solution


c^2 = (2N)^2 + (17)^2 -2(2)(17)*cos(45)
= 16 N
sin b/ 17N = sin45/16N
= 49 degrees

Fnet = 16 N (W 49 degrees N)

I am really confused with this unit. I don't know if I did it right, but I would appreciate feedback on where and how i went wrong.[/B]
diagrams-png.59601.png
A simpler way to find the net force of two or more vectors is to decompose each vector into its x and y components. Once that is done, the individual x and y components are added together algebraically, and the sum of these components gives you the component of the net force, or the resultant.

In b) above, the 8 N force has components of (0, 8) while the 10 N force has components (0, -10). The 17.0 N force can be converted to its components by completing the 45° triangle shown. Remember, a horizontal component pointing East is positive.
 
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