Calculate the net force acting on the object in the diagram

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SUMMARY

The discussion centers on calculating the net force acting on an object using vector decomposition and the Sine and Cosine Laws. The user attempted to find the net force in Diagram B, arriving at a resultant force of 16 N at an angle of 49 degrees. A more efficient method was suggested, involving the decomposition of vectors into their x and y components, which simplifies the calculation of the net force. The components of the forces were clarified, emphasizing the importance of correctly identifying positive and negative directions in vector analysis.

PREREQUISITES
  • Understanding of vector decomposition
  • Familiarity with Sine Law and Cosine Law
  • Basic knowledge of force components in physics
  • Ability to perform algebraic calculations with trigonometric functions
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  • Study vector decomposition techniques for force analysis
  • Learn about resolving forces into x and y components
  • Explore advanced applications of the Sine Law and Cosine Law in physics
  • Practice problems involving net force calculations in two-dimensional systems
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Students studying physics, particularly those focusing on mechanics and vector analysis, as well as educators seeking to clarify concepts related to force calculations.

roguekiller93
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Homework Statement


Calculate the net force in Diagram B.

Homework Equations


Sine Law: sin a/a = sin b/b = sin c/ c
Cosine Law: c^2 = a^2 + b^2 -2ab*cos(c)

The Attempt at a Solution


c^2 = (2N)^2 + (17)^2 -2(2)(17)*cos(45)
= 16 N
sin b/ 17N = sin45/16N
= 49 degrees

Fnet = 16 N (W 49 degrees N)

I am really confused with this unit. I don't know if I did it right, but I would appreciate feedback on where and how i went wrong.[/B]
diagrams-png.59601.png
 
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roguekiller93 said:

Homework Statement


Calculate the net force in Diagram B.

Homework Equations


Sine Law: sin a/a = sin b/b = sin c/ c
Cosine Law: c^2 = a^2 + b^2 -2ab*cos(c)

The Attempt at a Solution


c^2 = (2N)^2 + (17)^2 -2(2)(17)*cos(45)
= 16 N
sin b/ 17N = sin45/16N
= 49 degrees

Fnet = 16 N (W 49 degrees N)

I am really confused with this unit. I don't know if I did it right, but I would appreciate feedback on where and how i went wrong.[/B]
diagrams-png.59601.png
A simpler way to find the net force of two or more vectors is to decompose each vector into its x and y components. Once that is done, the individual x and y components are added together algebraically, and the sum of these components gives you the component of the net force, or the resultant.

In b) above, the 8 N force has components of (0, 8) while the 10 N force has components (0, -10). The 17.0 N force can be converted to its components by completing the 45° triangle shown. Remember, a horizontal component pointing East is positive.
 

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