Calculate the net force acting on the object

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The discussion focuses on calculating the net force acting on an object using vector components. The original calculations for the net force yielded 16 N, but the expected result is 16 N at an angle of W 40 N. Participants suggest using vector componentization to clarify the direction and magnitude of the resultant vector. The method involves breaking down the vectors into i and j components, summing them, and converting back to angle and magnitude. Accurate calculations are emphasized to avoid errors in determining the resultant vector's direction.
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1. Homework Statement

Calculate the net force acting on each object indicated in the following diagrams.
(diagrams attached) I am working on "B"

Homework Equations



Sine Law: sin a/a = sin b/b = sin c/ c
Cosine Law: c^2 = a^2 + b^2 -2ab*cos(c)

The Attempt at a Solution


C2 = (2W)2 + (17N)2 – 2(2)(17)Cos 45o

= 4 + 289 – 48.08326112

= 16 N
SinB/ 17 N = Sin 45 / 16 W

= 49o
∴ Net Force is 16 N (W49o N)
I am really struggling with this component of physics.I understand I got the wrong answer for the sine law because I rounded off too early in my cosine law calculations. However I am really struggling to understand how I got the wrong answer for the direction of my resultant vector. It is supposed to be 16 N [W 40 N].
 
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I can't see any attachment.
 
billy_joule said:
I can't see any attachment.
Sorry. I attached the diagrams now
 
It seems that if you componentized the vectors then added the components and then converted the resultant vector back to angle and magnitude.
 
jedishrfu said:
It seems that if you componentized the vectors then added the components and then converted the resultant vector back to angle and magnitude.
Yes. That's the method they want us to use.
 
So show us the i, j components of the vectors then show the components of the resultant one.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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