- #1

SuperHero

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## Homework Statement

Part of an elecrial circuit for the olympic score board consisted of a single battery V and several resistors having on of two values. R or 2R. They are hooked up in the confriguration as shown. Calculate the ratio of the two currents shown Ib/Ia

http://s1302.beta.photobucket.com/user/Rameel17/media/gggg_zps5b6383dc.jpg.html#/user/Rameel17/media/gggg_zps5b6383dc.jpg.html?&_suid=135753198581409194345584751531

## The Attempt at a Solution

So for Ib i did

Rt = R + 1/2R

Rt = 2R^2 /2R+ 1/2R

Rt = 2R^2 + 1 /2R

Ib = V/2R^2 + 1 /2R

Ib = V/4R^3 + 2R

for Ia

Rp = 1/2R + 1/2R + 1/2R +1/2R +1/2R +1/2R

Rp = 6/2R

Rs = R + R + R + R + R

Rs = 5R

Rt = 5R + 6/2R

Rt = 10R^2 + 6 / 2R

Ia = V / 10R^2 + 6/2R

Ia= V/ 20R^3 + 12R

Ib/Ia= V/4R^3 + 2R / V/ 20R^3 + 12R

= 20R^3 + 12R/4R^3 + 2R

= 2R (10R^2 + 6) / 2R (2R^2 + 1)

= (10R^2 + 6) /(2R^2 + 1)

i don't know what to do next