Calculate the ratio of new volume to old volume

  • Thread starter Thread starter Richie Smash
  • Start date Start date
  • Tags Tags
    Ratio Volume
Click For Summary
SUMMARY

The discussion focuses on calculating the ratio of new volume to old volume (V1/V2) of a car tire under constant pressure conditions, utilizing Charles' Law. The initial temperature is 23°C (296 K) and the final temperature is 34°C (307 K), with pressures of 2*105 Pa and 2.1*105 Pa respectively. The correct ratio of new to old volume is determined to be 1.04, derived from the ratio of final to initial temperatures, confirming the application of Charles' Law.

PREREQUISITES
  • Understanding of the General Gas Equation
  • Familiarity with Charles' Law
  • Basic knowledge of temperature conversion (Celsius to Kelvin)
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the General Gas Equation in detail
  • Explore applications of Charles' Law in real-world scenarios
  • Practice converting temperatures between Celsius and Kelvin
  • Learn about the behavior of gases under varying pressure and temperature conditions
USEFUL FOR

Students studying thermodynamics, physics enthusiasts, and anyone interested in understanding gas behavior under changing temperature and pressure conditions.

Richie Smash
Messages
293
Reaction score
15

Homework Statement


A car tyre has initial temperature 23°C and inital pressure 2*105 Pa
After heating in the sun, temperature is now 34°C and final pressure is 2.1*105Pa

Question asks, Calculate the ratio of new volume to old volume (V1/V2) if the pressure is held constant during the temperature rise stated above.

Homework Equations


General Gas Equation

(P1V1)/T1= (P2V2)/T2

The Attempt at a Solution


Using the general gas Equation I worked out the final pressure of 2.1*105Pa which was not orignially given.

Now for the ratio my idea is as follows

If the pressure is held constant, then V1/T1= V2/T2 which is a statement of charles Law.

I'm not sure how to find the ratio but perhaps if the ratio of new to old volume would be the same as the ratio between new and old temperature?

SO I would convert the celciusto kelvin by adding 273 and obtain 296 Kelvin initial temperature, and 307 K final temperature

Then I would do this 307/296 and that would give me 1.04 to two significant figures as the ratio.

Is this correct? I would like some assistance.
 
Last edited:
Physics news on Phys.org
Richie Smash said:
perhaps if the ratio of new to old volume would be the same as the ratio between new and old temperature?
That is what Charles' Law says. Just rearrange the equation to that form.
Richie Smash said:
Is this correct?
Yes.
 
Oh ok thanks a lot! I shall re arrange the equation for further clarification
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
876
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
16
Views
4K
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K