Calculate the resistance at 18 Celsius

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SUMMARY

The discussion focuses on calculating the resistance of a copper wire coil at two temperatures: 18 Celsius and 100 Celsius. The formula for resistance is established as R = ρ * L / A, where ρ is the resistivity of copper, L is the total length of the wire, and A is the cross-sectional area. Participants emphasize the importance of knowing the resistivity of copper and its temperature coefficient for accurate calculations. A recommended resource for finding this information is a specific online reference on copper resistivity.

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kEEhOLDEN
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cant do this question, well i can't figure out what I am supposed to do, whether its a thermistor or not, i worked out the inductance, but I am not sure what to do after that, here's the question

Calculate the resistance at 18 celsius of a 5cm diameter close-wound, single layer coil of 1000 turns of copper wire of 0.1mm diameter.

what would its approximate resistance be at a temperature of 100 celsius?

thanks
 
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Doesn't sound like they want the inductance -- sounds like they are asking for the resistance of the coil at two different temperatures. You need the rho of copper, and it's tempco (temperature coefficient). The total resistance R = rho*L/A, where L = total length, and A = area (of the wire cross-section in your case).

If you have a chem table book or EE reference book handy, you can find the info in there. Or easier is to just google the following:

+copper +resistivity +temperature

and the first hit you get will give you what you need:

http://hypertextbook.com/facts/2004/BridgetRitter.shtml

BTW, I'm kind of a newbie to the PF forums, so I just learned recently that questions like this are supposed to be posted in the HW forums. So now I try to check out the HW question forums to see if I can be of help.
 
thanks that's very helpful, i jus joined the forums, that was my first post, so i haven't a clue what is going on in here anyways, cheers
 

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