Calculate the solenoid dimension

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SUMMARY

This discussion focuses on calculating the thickness of a solenoid given specific parameters: a length of 20 cm, a magnetic field strength (B) of 5 Tesla, and a current (I) of 20 A. The relevant formula for calculating the magnetic field at the center of the solenoid is B = μ₀NI / √(4R² + l²), where N represents the number of loops and R is the radius. The thickness of the solenoid is directly dependent on the value of N, which is not provided in the discussion. Participants emphasize the importance of understanding the relationship between these variables to accurately determine the solenoid's dimensions.

PREREQUISITES
  • Understanding of solenoid physics and magnetic fields
  • Familiarity with the formula B = μ₀NI / √(4R² + l²)
  • Knowledge of electromagnetic principles, specifically related to current and magnetic fields
  • Basic mathematical skills for manipulating equations
NEXT STEPS
  • Research the calculation of the number of loops (N) in a solenoid
  • Study the effects of solenoid dimensions on magnetic field strength
  • Explore variations in solenoid design for higher magnetic fields
  • Learn about the applications of solenoids in electromagnetic devices
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Engineers, physicists, and students involved in electromagnetism, particularly those working on solenoid design and magnetic field applications.

mdpai
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Hi to all,

I have a problem to share with you guys.

How can I calculate the thickness of my solenoid if I have these values;

Solenoid long : 20cm
magnetic field, B : 5Tesla
Current, I : 20A

Thanks a lot for your help. I appreciate that
 
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5T, yeah I know , it's a lot. is it possible?
 
B=μnI this is only valid if the proportion between the thickness and the longeur is huge.
 
mdpai said:
5T, yeah I know , it's a lot. is it possible?

Since stronger magnets have been built, it's possible.
Within any construction constraints you might have, no idea.
Good luck with that.
 
At which place is regarding to solenoid B=5\;T?

For example,formula for B in center of solenoid is:

B=\frac{\mu_0NI}{\sqrt{4R^2+l^2}}
 
R A V E N said:
At which place is regarding to solenoid B=5\;T?

For example,formula for B in center of solenoid is:

B=\frac{\mu_0NI}{\sqrt{4R^2+l^2}}

It's in the air at the center of the solenoid.

p/s:
I found a formula

B=\frac{\mu_0NI}{\sqrt{R^2+l^2}}

So now I confuse, it's 4R^2 or R^2?
 
You are right,it is error in my book.But still you don`t have N given.:confused:
 
the thickness of the solenoid depends on the value of N. So, I don't know if we have to calculate N first or, directly calculate the value of the thickness
 
  • #10
mdpai said:
the thickness of the solenoid depends on the value of N.

:confused:

N is number of loops.
 

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