Calculate the Sum of Series: \sum_{n=1}^{\infty}n(n+1)x^n for Homework

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SUMMARY

The series sum \(\sum_{n=1}^{\infty}n(n+1)x^n\) can be calculated using the formula \(x\frac{d^2}{dx^2}\frac{x^2}{1-x}\). The initial steps involve manipulating the series into a form suitable for differentiation, specifically \(x\sum_{n=1}^{\infty}n(n+1)x^{n-1}\). It is crucial to apply the quotient rule correctly when taking the second derivative of \(\frac{x^2}{1-x}\), ensuring that the denominator is squared in each derivative step.

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Homework Statement


Find the sum of the following series

[tex]\sum_{n=1}^{\infty}n(n+1)x^n[/tex]


The Attempt at a Solution




[tex]x\sum_{n=1}^{\infty}n(n+1)x^{n-1}[/tex]

[tex]x\int_{0}^{x}(\int_{0}^{x}f(t)dt)dt=x(x^2+x^3+x^4+x^5+\cdots)=x\frac{x^2}{1-x}[/tex]


[tex]x\frac{d^2}{dx^2}\frac{x^2}{1-x}=\frac{2x}{1-x}[/tex]
 
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I am not really sure of how to do this but looking at your last line, I think you messed up taking the second derivative of x^2/(1-x) since you need to use the quotient rule, the (1-x) should be squared on each derivative
 

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